27x^-36x^2+12x=0

Solution for 27x^-36x^2+12x=0 equation:

27x^-36x^2+12x=0

We add all the numbers together, and all the variables

-36x^2+39x=0

a = -36; b = 39; c = 0;
Δ = b2-4ac
Δ = 392-4·(-36)·0
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1521}=39$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(39)-39}{2*-36}=\frac{-78}{-72}
=1+1/12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(39)+39}{2*-36}=\frac{0}{-72}
=0
$